bettina@coasterch

I have 2 tables (simplified):

coasters (COASTER_CODE, BREWERY_CODE, etc)
breweries (BREWERY_CODE, BREWERY)

For each brewery I want to count how many coasters are there in table
"coasters" (up to here it works fine) and then I want to show them
ordered by quantity (that's my problem):

The following is the piece of code.

$search_breweries = mysql_query("SELECT b.BREWERY_CODE, b.BREWERY,
COUNT(c.COASTER_CODE) FROM breweries as b JOIN coasters as c ON
b.BREWERY_CODE = c.BREWERY_CODE Group by b.BREWERY_CODE order by
COUNT(c.COASTER_CODE) DESC ");
$i = 0;
while ($row = mysql_fetch_array($search_breweries, MYSQL_NUM)) {
$mybreweries[$i][0] = $row[0];
$mybreweries[$i][1] = $row[1];
$mybreweries[$i][2] = $row[2];
$i = $i + 1;
}
......
I get the following message:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
result resource in....

Any help will be welcomed!

jerry stuckle

Your query failed. Always check the return value from mysql_query:

$search_breweries = mysql_query("SELECT b.BREWERY_CODE, b.BREWERY,
COUNT(c.COASTER_CODE) FROM breweries as b JOIN coasters as c ON
b.BREWERY_CODE = c.BREWERY_CODE Group by b.BREWERY_CODE order by
COUNT(c.COASTER_CODE) DESC ");
if ($search_breweries) {
$i = 0;
while ($row = mysql_fetch_array($search_breweries, MYSQL_NUM)) {
$mybreweries[$i][0] = $row[0];
$mybreweries[$i][1] = $row[1];
$mybreweries[$i][2] = $row[2];
$i = $i + 1;
}
else
echo mysql_error();


--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
==================

bettina@coasterch

Thank you for your answer. I get the message: Invalid use of group
function
Hat something to do with the "count" function?

Jerry Stuckle schrieb:

bettina@coasterch

$search_breweries = mysql_query("SELECT b.BREWERY_CODE, b.BREWERY,
COUNT(c.ID) as cant FROM breweries as b JOIN coasters as c ON
b.BREWERY_CODE = c.BREWERY_CODE Group by b.BREWERY_CODE order by cant
DESC ");