$2 contains "abc:def"
while [ 1]
do
count=0
status[$count]=`echo "$2" | awk -F: '{ print $count }'`

when we execute the above command status[1] should get "abc and
status[2] should get def...
but it does not work....can somebody advice.....

count=$((count+1));

---do soemthing.......

done

ed morton

This is the correct syntax for what you're trying to do:

status[$count]=`echo "$2" | awk -F: -v cnt="$count" '{ print $cnt }'`

See question 24 in the comp.unix.shell FAQ,
http://home.comcast.net/~j.p.h/cus-faq-2.html#24.

Having said that, the above script doesn't make sense because you're
setting count to zero every time round the loop and you don't need awk
to do what you want anyway. You should post a questioin to
comp.unix.shell asking for help on generally fixing the script.

Ed.

loki harfagr

Le Wed, 13 Sep 2006 07:06:59 -0500, Ed Morton a écrit*:


Yes, and now I just can't wait to see coming in comp.unix.shell
a post entitled "SHELL" ;D)