bpetria

Hi,

I am trying to print solid horizontal lines on a Panasonic KX-P1180 dot
matrix printer in graphics mode. The printer book list the command for double
density graphics (960 dots per line) as (dec) "27, 76, n1, n2, Data"
I do not know if "n1, n2" is suppose to represent the number of
times to print "Data" or what? Is "Data" a single number from
0 - 255 (dec) which represents an 8 bit sequence to print?

Thanks in advance, Brad

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anoneds

n1 and n2 are # of dots (horizontal resolution) of the image. This is
all off the top of my head... actually, I edited this by finding my
old Gemini 10x manual.
#dots=n1+*256*n2
This should be followed by the data (1 byte per horizontal dot). So if
#dots=720, you'd have 720 bytes.
These bytes depend on your printer. If your mode supports 8-bit, each
byte is a 1x8 strip (vertical). The numbering begins at the bottom of
your character. Say you want to print this character: (0 - off 1 - on)

00100
00100
00100
11111
00100
00100
00100
00100

A "+" in an 8x5 representation. n1=5, n2=0 The first column is, from
the bottom, "00001000".
This is 0*2^0+0*2^1+0*2^2+0*2^3+1*2^3+0*2^4+0*2^5+0*2^6+0* 2^7=8 (first
byte)
This is 0*2^0+0*2^1+0*2^2+0*2^3+1*2^3+0*2^4+0*2^5+0*2^6+0* 2^7=8 (2nd
byte)
This is 1*2^1+1*2^1+1*2^2+1*2^3+1*2^3+1*2^4+1*2^5+1*2^6+1* 2^7=255
(third byte)
This is 0*2^0+0*2^1+0*2^2+0*2^3+1*2^3+0*2^4+0*2^5+0*2^6+0* 2^7=8
(fourth byte)
This is 0*2^0+0*2^1+0*2^2+0*2^3+1*2^3+0*2^4+0*2^5+0*2^6+0* 2^7=8 (fifth
byte)

So, you should print chr$(x), for x={27,76,5,0,8,8,255,8,8}

Beware of chr$(13) being generated, as Basic likes to add a LF to a
CR.
The old Gemini had a setting for 7/72 line feed so you could ignore
the first bit. But my old TI-99 didn't have the chr$(13) problem, so I
could use all the pins at once...

Ben

Someone who remembers too much. The only part I had to change above
was I had "n1*256+n2"...

anoneds

Oops, better editing next time #dots=n1+256*n2

Ben

bob may

N1 and so forth will be defined at either the beginning or the end of the
list of codes.

--
There are more Democrats on the Calif. Special Election than Republicans!
Go count if you don't believe me!
Bob May