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2
4th July 11:02
External User
Posts: 1
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Of course we must have E A = E N D = B D, i.e. a m (m+1) = b n (n+1).
Then the entries N_{1,j} and N_{i,1} can be expressed in terms of the others: N_{1,j} = b - sum_{i=2}^m i N_{i,j} for j > 1 N_{i,1} = a - sum_{j=2}^n j N_{i,j} for i > 1 N_{1,1} = b - sum_{i=2}^m i N_{i,1} = b - a (m+2)(m-1)/2 + sum_{i=2}^m sum_{j=2}^n i j N_{i,j} If the N_{i,j} for i=2..m, j=2..n are integers, then so are the N_(1,j) and N_(i,1). All that remains is to ensure that these are nonnegative. Robert Israel israel@math.ubc.ca Department of Mathematics http://www.math.ubc.ca/~israel University of British Columbia Vancouver, BC, Canada |
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