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1 28th December 08:35
dana.king
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Posts: 1
Default Math Help: Second Derivative



Help,

My teacher assigned an extra assignment for our class, to help boost
our grades for University application. Unfortunately, I have been
unable to solve one of the problems. My teacher gave us the fully
simplified answer, but I have been unable to get the same answer.

The question reads: Given: 4x^2 - 5y^2 = -1, find d^2y/dx^2 Simplify
Fully.

The answer is: 4/25 y^3 <----How do i get this?

Any help with this solution would be greatly, appreciated.

Thank you
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2 28th December 08:35
julian v. noble
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Posts: 1
Default Math Help: Second Derivative



It is not surprising that you can't get the answer above. It is
wrong. The correct answer is

y'' = (4/25) y^{-3}

I suggest you differentiate the original relation w.r.t. x, solve
for y', differentiate again, and eliminate y' and x using the
original expression and the expression for y' . The rest is algebra.

--
Julian V. Noble
Professor Emeritus of Physics
jvn@lessspamformother.virginia.edu
^^^^^^^^^^^^^^^^^^
http://galileo.phys.virginia.edu/~jvn/

"For there was never yet philosopher that could endure the
toothache patiently."

-- Wm. Shakespeare, Much Ado about Nothing. Act v. Sc. 1.
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3 28th December 08:36
dana.king
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Posts: 1
Default Math Help: Second Derivative


href="http://galileo.phys.virginia.edu/~jvn/">http://galileo.phys.virginia.edu/~jvn/</a>


HELP!
What does w.r.t. mean? And could you show me the work for this
question
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4 28th December 08:36
david w. cantrell
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Posts: 1
Default Math Help: Second Derivative


It means "with respect to".


I'm sure he could, as could I. But this is a problem that _you_ are
supposed to do. JVN has already provided you with a nice outline of
the necessary steps; you should be able to do the rest yourself if
you are to deserve the extra credit.

David
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5 28th December 08:36
julian v. noble
External User
 
Posts: 1
Default Math Help: Second Derivative


^^^^^^

"with respect to" -- it's a standard abbreviation.


When Hell freezes over. Try to act a little bit
grateful when someone helps you, even if you don't
really feel that way.

Nobody here really gives a Tinker's damn (look it
up!) whether you get extra credit or not. Some of
us might care whether you learn something, however,
since we would hate to fly a plane, or cross a bridge
that you might design, if you don't learn a little math. ;-)


--
Julian V. Noble
Professor Emeritus of Physics
jvn@lessspamformother.virginia.edu
^^^^^^^^^^^^^^^^^^
http://galileo.phys.virginia.edu/~jvn/

"You catch more flies with honey than with vinegar."

-- one of my Grandma's sayings. Take it to heart.
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6 29th December 22:59
ken pledger
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Posts: 1
Default Math Help: Second Derivative


Right. I saw the question under a different title, and probably
gave too much help before finding this thread. It may be too late to
matter anyway.

Ken Pledger.
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