Transcendentals
Before Robert closes the thread, let me make my conjecture as best as I can:
Call a "morphism" a pattern of digits a(n) which is in one to one correspondence
with the naturals and further it has the property a(n)+a(m)=a(n+m).
For example, the decimal patterns of C_2 (Champernowne's base 2 pattern) are a
morphism, because they can be mapped directly onto the Naturals and they satisfy
a(n)+a(m)=a(n+m). So are the patterns of C_b, where b is any base in {2,..10}.
Simply associate the number 1 with its base b pattern, 2 with its base b
pattern, and so on.
Although a general non-trivial sequence gives a one to one correspondence
between N and its terms {a(n)}, n\in N, the pattern it generates
(0.a(1)a(2)a(3)...) is not necessarilly a morphism. Take a(n)=floor(exp(n)), for
example: a(1)+a(2)=2+7 =/= a(3)=20.
The case I have and I am interested in is the sequence a(n) described in this
webpage:
http://ioannis.virtualcomposer2000.com/math/Naturals.html
Although it looks that this a(n) is not a morphism
(a(1)+a(2)=102+101022=/=101021010222=a(3)), on another level it looks like *it
is* a morphism, since the word for a(n) is essentially nothing but a string
representation of all the preceding naturals, 012...n-1, therefore a(n) is
basically a different representation of n itself.
On some level then (which sorry, I cannot put to words) c(n) is essentially
Champernowne's expansion, expressed using different symbols. Therefore it looks
as if A is transcendental iff C_{10} is.
I am sorry, this is the best I can do to describe the problem. I seem to be
lacking the description tools in this case.
--
I.N. Galidakis --- http://ioannis.virtualcomposer2000.com/
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