Vladimir bonda2012-04-13 00:10:33

Hello the symbolic computation ladies and gentlemen ;),

Is there a person who can show how to calculate using a set of

Maple operations the exact value of the following integral

int(hypergeom([-1/2, 1/4],[1/2],z/2)/(z-z^2)^(1/4), z= 0..1);

?

(I’d propose you don’t waste much time with identify() here ðŸ˜‰

Best wishes,

Vladimir Bondarenko

VM and GEMM architect

Co-founder, CEO, Mathematical Director

http://www.cybertester.com/ Cyber Tester, LLC

http://maple.bug-list.org/ Maple Bugs Encyclopaedia

http://www.CAS-testing.org/ CAS Testing

C w2012-04-13 00:10:36

Is it :

2*GAMMA(3/4)^2/Pi^(1/2)*hypergeom([3/4, 1/4, -1/2],[3/2, 1/2],1/2); ?

Vladimir bonda2012-04-13 00:37:22

C W

writes on Thu, Mar 30 2006 4:56 am

CW> Is it :

CW> 2*GAMMA(3/4)^2/Pi^(1/2)*hypergeom([3/4, 1/4, -1/2],

CW> [3/2, 1/2],1/2);

Gee! ðŸ˜‰

evalf(2*GAMMA(3/4)^2/Pi^(1/2)*hypergeom([3/4, 1/4, -1/2], [3/2,

1/2],1/2), 60);

evalf(-1/8*(3*ln(2)-2^(1/2)*(4-2*2^(1/2))^(1/2)+4*(4-2*2^(1/2)

)^(1/2)+2^(1/2)*(4+2*2^(1/2))^(1/2)+4*(4+2*2^(1/2))^(1/2)-2*ln

(2+(4-2*2^(1/2))^(1/2))-2*ln(2+(4+2*2^(1/2))^(1/2))-4*2^(1/4)*

(2^(1/2)+1)^(1/2)-8*2^(3/4)*(2^(1/2)+1)^(1/2)+4*ln(2^(1/4)+(2^

(1/2)+1)^(1/2)))*2^(1/2)*GAMMA(3/4)^2/Pi^(1/2), 60);

evalf(Int(hypergeom([-1/2, 1/4], [1/2], z/2)/(z-z^2)^(1/4), z=

0..1), 60);

1.57896721214319355170497099979271421403775053272417210529762

1.57896721214319355170497099979271421403775053272417210529761

1.57896721214319355170497099979271421403775053272417210529762

It would be great if you think you could tell us the train of

your thoughts…

ðŸ˜‰

## Leave a Reply

You must be logged in to post a comment.